The question : Seek the value and maximum value of the path from the top to the next , The problem came out in the competition But at that time, I couldn't understand the title and didn't write it , It's like a digital triangle , Just added the bottom part of him , It can be divided into two situations .

AC Code ：

#include<cstdio>
#include <cstring>
#include <iostream>
using namespace std;
int i,j,n;
long long a[][],f[][],ans;
int main()
{
int t2;
scanf("%d",&t2);
for(int t1 = ; t1 <= t2; t1++)
{
scanf("%d",&n);
for(i = ; i <= *n-; i++)
for(j = ; j <= min(i,*n - i); j++)
{
scanf("%lld",&a[i][j]);
}
memset(f,,sizeof(f));
for(i = ; i <= *n-; i++)
for(j = ; j <= min(i,*n - i); j++)
{
if(i == ) f[i][j] = a[i][j];
if(i<=n)
{
f[i][j] = max(f[i-][j], f[i - ][j - ]) + a[i][j];
}
else
{
f[i][j] = max(f[i-][j], f[i - ][j + ]) + a[i][j];
}
}
printf("Case %d: %lld",t1,f[*n-][]);
putchar('\n'); }
return ;
}

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