To Luogu .2242 Highway maintenance problems

## Title Description

Because it hasn't been repaired for a long time ,A On the freeway of our country appeared N Pit . In order to fill the gap as soon as possible N Pit ,A The U.S. decided to M Traffic control in this area . For the convenience of solving , hypothesis A There is only one highway in China , And it's straight . Now give N The location of the pit , Please calculate , At least how far to control traffic ？

## I / O format

Input format ：

There are two lines of input data , The first line is two positive integers N、M （2<=N<=15000,M<=N）. The second line gives N The coordinates of a pit （ The coordinate values are all in the long integer range , From small to large , And there won't be two points with the same coordinates ）.

Output format ：

Just one line , Is the minimum length and .

## I/o sample

sample input #1：

```18 4
3 4 6 8 14 15 16 17 21 25 26 27 30 31 40 41 42 43
```
sample output #1：

`25`

## explain

[ Sample explanation ]

The traffic control areas are ：3-8,14-21,25-31,40-43.

## Code ：

``` #include<cstdio>
#include<algorithm>
using namespace std;
int n,m,num,last,Ans,Delta[];
int main()
{
scanf("%d%d",&n,&m);
for(int i=;i<=n;i++)
{
scanf("%d",&num);
Delta[i]=num-last;
last=num;
}
//n Number There is n-1 An interval , It can be used m-1 individual 0 Fill in the biggest gap ,
// Add the rest . Because each segment includes two ends (a-b+1), Less calculation 1, So at the end of the day m
/*for(int i=1;i<=n;i++)
printf("%d:%d\n",i,Delta[i]);*/
sort(Delta+,Delta++n);// Remove the first element from 0 Distance between
for(int i=;i<=n-m+;i++)// Ignore Delta[1]
Ans+=Delta[i];
printf("%d",Ans+m);
return ;
}```

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