## Problem description

Given array a[N], Can be determined C(N,2) A point is right , That's for sure C(N,2) Distance , Find the second of these distances k A small distance （k<C(N,2)）.

## Ideas

See the k Small 、 The first k It's a big problem , First think of dichotomy .

Turn the evaluation problem into ： How many elements are less than this value .

The interval problem of this problem needs careful consideration , Consider the need for an equal sign in all places where a less than sign appears .

## Code

``````class Solution:
def smallestDistancePair(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
nums = sorted(nums)
l = 0
r = nums[-1] - nums[0]
def find(m):
s = 0
j = 0
for i in range(len(nums)):
while j < len(nums) and nums[j] - nums[i] <= m:
j += 1
s += j - i - 1
return s
while l< r:
m = (l + r) // 2
s = find(m)
if s >= k:
r = m
else:
l = m+1
return l
``````

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