## Problem description

Given array a[N], Can be determined C(N,2) A point is right , That's for sure C(N,2) Distance , Find the second of these distances k A small distance （k<C(N,2)）.

## Ideas

See the k Small 、 The first k It's a big problem , First think of dichotomy .

Turn the evaluation problem into ： How many elements are less than this value .

The interval problem of this problem needs careful consideration , Consider the need for an equal sign in all places where a less than sign appears .

## Code

`class Solution:`

def smallestDistancePair(self, nums, k):

"""

:type nums: List[int]

:type k: int

:rtype: int

"""

nums = sorted(nums)

l = 0

r = nums[-1] - nums[0]
def find(m):

s = 0

j = 0

for i in range(len(nums)):

while j < len(nums) and nums[j] - nums[i] <= m:

j += 1

s += j - i - 1

return s
while l< r:

m = (l + r) // 2

s = find(m)

if s >= k:

r = m

else:

l = m+1

return l

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