link ：https://pintia.cn/problem-sets/994805046380707840/problems/994805068539215872

subject ：

Give everyone's family members and their own properties , Please count the population of each family 、 Per capita real estate area and number of real estate units .

### Input format ：

The first line of input gives a positive integer N（≤）, And then N That's ok , Each line gives a person's property in the following format ：

` Number Father mother k children 1 ... children k Number of real estate units Total area `

among ` Number `

It's a unique one for everyone 4 Number of digits ;` Father `

and ` mother `

They are the numbers of the parents of the corresponding person （ If you have passed away , Is displayed `-1`

）;`k`

（0`k`

≤） It's the number of children of the person ;` children i`

Is the number of their child .

### Output format ：

First, output the number of families in the first line （ All relatives belong to the same family ）. Then output the information of each family in the following format ：

` Minimum number of family members The number of families Per capita number of real estate units Per capita real estate area `

The per capita value shall be kept after the decimal point 3 position . Family information is first output in descending order of per capita area , If there is juxtaposition , Then output... In ascending order of member number .

### sample input ：

`10`

6666 5551 5552 1 7777 1 100

1234 5678 9012 1 0002 2 300

8888 -1 -1 0 1 1000

2468 0001 0004 1 2222 1 500

7777 6666 -1 0 2 300

3721 -1 -1 1 2333 2 150

9012 -1 -1 3 1236 1235 1234 1 100

1235 5678 9012 0 1 50

2222 1236 2468 2 6661 6662 1 300

2333 -1 3721 3 6661 6662 6663 1 100

### sample output ：

`3`

8888 1 1.000 1000.000

#include <iostream>

#include <cstdio>

#include <cstdlib>

#include <cmath>

#include <string>

#include <cstring>

#include <algorithm> using namespace std;

typedef long long ll;

typedef unsigned long long ull;

const int inf=0x3f3f3f3f;

const int maxn=1e4+;

int n,p1,p2,k,d;

int fa[maxn],vis[maxn]; struct node{

int id;

double ans,sum;

}kk[maxn]; struct he{

int id,num,ans,sum;

double avgans,avgsum;

}final[maxn]; void init(){

for(int i=;i<;i++){

fa[i]=i;

final[i].id=;

final[i].num=;

final[i].ans=;

final[i].sum=;

final[i].avgans=;

final[i].avgsum=;

}

} int cmp(he a,he b){

if(a.avgsum==b.avgsum) return a.id<b.id;

else return a.avgsum>b.avgsum;

} int find(int x){

if(fa[x]==x) return x;

else return fa[x]=find(fa[x]);

} void unite(int x,int y){

x=find(x);

y=find(y);

if(x==y) return;

else fa[y]=x;

} int main(){

init();

scanf("%d",&n);

for(int i=;i<=n;i++){

scanf("%d%d%d",&kk[i].id,&p1,&p2);

vis[kk[i].id]=;

if(p1!=-){

unite(kk[i].id,p1);

vis[p1]=;

}

if(p2!=-){

unite(kk[i].id,p2);

vis[p2]=;

}

scanf("%d",&k);

for(int j=;j<=k;j++){

scanf("%d",&d);

unite(kk[i].id,d);

vis[d]=;

}

scanf("%lf%lf",&kk[i].ans,&kk[i].sum);

}

for(int i=;i<=n;i++){

int tmp=find(kk[i].id);

final[tmp].ans+=kk[i].ans;

final[tmp].sum+=kk[i].sum;

}

for(int i=;i<;i++){

if(vis[i]){

fa[i]=find(i);

if(!final[fa[i]].num)

final[fa[i]].id=i;

final[fa[i]].num++;

final[fa[i]].avgans=final[fa[i]].ans*1.0/final[fa[i]].num;

final[fa[i]].avgsum=final[fa[i]].sum*1.0/final[fa[i]].num;

}

}

int ans=;

sort(final,final+,cmp);

for(int i=;i<;i++){

if(final[i].num) ans++;

else break;

}

printf("%d\n",ans);

for(int i=;i<ans;i++){

printf("%04d %d %.3f %.3f\n",final[i].id,final[i].num,final[i].avgans,final[i].avgsum);

}

return ;

}

0001 15 0.600 100.000

5551 4 0.750 100.000

Ideas ：

The point is to find every family Use and search to connect all of a family to an ancestor Every time you read in, parents and children do it and look it up

The trouble is that you have to deal with a lot of data More complicated

First, connect the parents and children in the same family And then recycle it Update the total number of rooms and total area of the family I'm going to go through the loop again and find the average Then output it

Code ：

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