N A box in a circle , The first i The first box had Ai A little ball , You can move a ball from one box to one of the two adjacent boxes at a time . How many times should I move at least so that the number of balls in each box does not exceed 1.


Minimum cost and maximum flow .

Each box serves as a point .

if Ai>1 Then from the source point to this point, connect a line with the capacity of Ai, The cost is 0 The edge of .

if Ai=0 From this point to the sink point, connect a line with a capacity of 1, The cost is 0 The edge of .

Each box has a positive infinity to two adjacent boxes , The cost is 1 The edge of .

Minimum cost and maximum flow is the answer .

using namespace std;
const int dian=;
const int bian=;
const int INF=0x3f3f3f3f;
int h[dian],nxt[bian],ver[bian],val[bian],cos[bian],with[dian],minn[dian];
int d[dian],v[dian];
int map[dian];
int n,tot;
int S,T;
void add(int a,int b,int c,int d){
bool tell(){
int x=q.front();
for(int i=h[x];i;i=nxt[i]){
int y=ver[i];
return ;
return ;
int zeng(){
for(int i=T;i!=S;i=ver[with[i]^]){
return minn[T]*d[T];
int dinic_cost(){
int r=;
return r;
int main(){
int cas;
for(int i=;i<=n;i++)
for(int i=;i<=n;i++){
else if(!map[i])
return ;

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